29. Divide Two Integers
Problem:
Given two integers dividend
and divisor
, divide two integers without using multiplication, division and mod operator.
Return the quotient after dividing dividend
by divisor
.
The integer division should truncate toward zero.
Example 1:
Input: dividend = 10, divisor = 3
Output: 3
Example 2:
Input: dividend = 7, divisor = -3
Output: -2
Note:
- Both dividend and divisor will be 32-bit signed integers.
- The divisor will never be 0.
- Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 231 − 1 when the division result overflows.
Solution:
Every decimal number can be represented as a0*2^0 + a1*2^1 + a2*2^2 + ... + an*2^n
.
Replace multiplication and division with binary shifting.
/**
* @param {number} dividend
* @param {number} divisor
* @return {number}
*/
let divide = function (dividend, divisor) {
if (divisor === 0 || (divisor === -1 && dividend < -2147483647) || dividend > 2147483647 || dividend < -2147483648) {
return 2147483647;
}
const isNegative = (dividend < 0 && divisor >= 0) || (dividend >= 0 && divisor < 0);
const pDividend = Math.abs(dividend);
const pDivisor = Math.abs(divisor);
if (dividend === 0 || pDividend < pDivisor) {
return 0;
}
let doubling = pDivisor;
let count = 1;
while (doubling < pDividend && !(doubling & (1 << 30))) {
doubling <<= 1;
count <<= 1;
}
if (doubling > pDividend) {
doubling >>>= 1;
count >>>= 1;
}
const result = count + divide(pDividend - doubling, pDivisor);
return isNegative ? -result : result;
};
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☆: .。. o(≧▽≦)o .。.:☆☆: .。. o(≧▽≦)o .。.:☆